17x^2=1

Solution for 17x^2=1 equation:

17x^2=1

We move all terms to the left:

17x^2-(1)=0

a = 17; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·17·(-1)
Δ = 68
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{68}=\sqrt{4*17}=\sqrt{4}*\sqrt{17}=2\sqrt{17}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{17}}{2*17}=\frac{0-2\sqrt{17}}{34}
=-\frac{2\sqrt{17}}{34}
=-\frac{\sqrt{17}}{17}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{17}}{2*17}=\frac{0+2\sqrt{17}}{34}
=\frac{2\sqrt{17}}{34}
=\frac{\sqrt{17}}{17}
$